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vsgdp science forum addict
Joined: 01 May 2005
Posts: 78
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Posted: Wed May 04, 2005 2:54 am Post subject:
norms
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Hi,
I need to show ||f|| = integral( abs(f) dx, a, b) is a norm on the set of
continuous functions on [a, b].
I know I need to show the 4 properties, but in particular, I am having
trouble showing triangle inequality. Basically, the absolute value is
giving me problems. Any hints? |
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A. Boom science forum addict
Joined: 28 Apr 2005
Posts: 65
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Posted: Wed May 04, 2005 3:32 am Post subject:
Re: norms
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vsgdp wrote:
| Quote: | Hi,
I need to show ||f|| = integral( abs(f) dx, a, b) is a norm on the set of
continuous functions on [a, b].
I know I need to show the 4 properties, but in particular, I am having
trouble showing triangle inequality. Basically, the absolute value is
giving me problems. Any hints?
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I've never done what you are attempting, but might you show the
inequality hold for integral( f dx, a, b) and also integral (-f dx, a,
b), and if it holds for both then it holds for integral (abs(f) dx, a, b).
Adam. |
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Proginoskes science forum Guru
Joined: 29 Apr 2005
Posts: 2593
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Posted: Wed May 04, 2005 4:13 am Post subject:
Re: norms
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vsgdp wrote:
| Quote: | Hi,
I need to show ||f|| = integral( abs(f) dx, a, b) is a norm on
the set of continuous functions on [a, b].
I know I need to show the 4 properties, but in particular, I
am having trouble showing triangle inequality. Basically, the
absolute value is giving me problems. Any hints?
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Use the property of integrals that says if F(x) <= G(x) for all x
in the interval, then
integral (F(x) dx, a, b) <= integral( G(x) dx, a, b),
along with the triangle inequality for real numbers.
This should be more than enough of a hint.
--- Christopher Heckman |
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