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 Posted: Fri Jun 10, 2005 8:08 am Post subject:
hypergeometric GF: difficult sum
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Here is the next challenge. Using Mathematica notation, define
g[m_,z_] = z HypergeometricPFQ[{1, 1, 2m - 1}, {2, m + 1/2}, -z/4]/(2 m
- 1);
Then evaluate in closed form the infinite sum (with two
independent variables: y and z)
s = Sum[g[m,z] y^(m-1), {m, 1, Infinity}];
Mathematica returns it unevaluated. |
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