brian a m stuckless
science forum Guru
Joined: 31 Aug 2005
Posts: 2024
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 Posted: Wed Jun 21, 2006 1:57 pm Post subject:
Electro REST Math=eM/c^2.
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$$ Sue... wrote: > > guskz@hotmail.com wrote: > > snip > >
| Quote: | So you're saying instead of applying the total charges in space to the
equation and using "k for space", they are varying "k" instead so as
to include the charges in the medium (as opposed to the charges outside
the medium)?
Whether charges exist ~outside the medium~ or not
does not concern us. If they are absent, their charge is
zero. If they are present, they exist in e+ e- pairs so
their value is zero.
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$$ Clearly, the SUM of all the + & - charges isN'T ZERO.
$$ This is where you dimwits need a lesson in "ENTHALPY".
$$ Total Hamiltonian ENTHALPY includes all ..whatever sign.
$$ YOU have to provide a mathematical way to CHANGE the sign.
$$ [This has been provided to you over & over & over ..again].
$$
$$ Again ..SUM Enthalpy = (LaGrangian L) + Gibb's eG
$$ = (m*v^2/2)*(m/M + 1) + Newton's G*M*m/(n-1)*r.
$$
$$ Where NOTE (n - 1) exactly dictates what will be the proper sign.
$$ Where NOTE (n - 1) exactly dictates what is the AMBiENT media #.
$$ Where NOTE (n - 1) exactly dictates what is the CHARGE density.
$$ [The GUESS iSS modified Couloumb~Newton equation already done].
$$ [Re: GUESS iSS modified Couloumb~Newton < REST Math=eM/c^2 > ].
$$
$$ How many more times? Duh, here it is again:
$$ Hamiltonian ENTHALPY E - Kinetic energy eK = E - L - eV = REST eM
$$
$$ | G*M1*m1 k_c*q1*q2|
$$ Force*rA = |-- -- - -- + -- -- - --| = |(LaGrangian L) + eF| = eM
$$ |(n - 1)*rA (n - 1)*rA|
$$
$$ | m1*v1^2 | |3*m1*rA*(g + a)|
$$ = |Gibbs eG + (-- - --)| = |-- -- --- -- --| = (eG - eV) = m*c^2
$$ | 2 | | 2 |
$$
$$ | m1^2*v1^2 | | m1*v1^2 m1 |
$$ = E - eK = |E - (-- --- --)| = |E - {(-- - --)*(-- + 1)} - eV|
$$ | 2*M1 | | 2 M1 |
$$ |E - ( eK )| |E - { LaGrangian L } - eV|
$$
$$ = iNTRiNSiC REST energy of the ground state, for iSOLATED systems.
$$
$$ E=eG, eM=eF and eK=eV ONLY if Ti in LaGrangian L COULD be zero (0).
$$ The SAME rA for M1*m1 ORBiT distance ..is ESCAPE radius, for q1*q2.
$$ SAME M1*m1 ORBiT rA = v1^2/g = ESCAPE vesc^2/2(n - 1)*a, for q1*q2.
$$ [Note +(m1*v1^2/2) CANNOT be EQUAL to -eV at ONCE per calculation].
$$ Also, note ..ALL is the SAME, in GUESS PLANCK Temperature Tp units.
$$ And finally, icon * is a MULTiPLiCATiON SiGN which SEPARATEs icons.
$$
$$ This ought help a bit. Sincerely, Brian.
| Quote: | Try to remember that on a grand scale, every positive charge is
canceling out a negative charge. It is not the same a summing
up the mass of all the atoms in the universe.
So the universe has a total charge of zero, but its mass
is non-zero. > > > > Sue... > snip
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Re: Since k varies but not G suggests an Eather.
Re: [Electro] REST Math=eM/c^2. End of POST. |
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