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Dave Seaman science forum Guru
Joined: 24 Mar 2005
Posts: 527

Posted: Wed Jul 12, 2006 12:21 pm Post subject:
Re: Probability of 1234567890



On Wed, 12 Jul 2006 05:30:22 GMT, Andrew Poelstra wrote:
Quote:  On 20060712, Dave Seaman <dseaman@no.such.host> wrote:
On Wed, 12 Jul 2006 02:41:04 GMT, Andrew Poelstra wrote:
On 20060711, Stig Holmquist <stigfjorden@hotmail.com> wrote:
What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?
Well, the number of permutations of 1234567890 is 10!
So, you have 10!/(10x10^10)
The number of ways of selecting 10 balls when sampling with replacement
is 10^10, not 10^11.
10*10^10 is 10^11. (I'm not sure if you factored that into your post or
not).

The correct number of outcomes is 10^10, not 10^11. If you were drawing
11 times with replacement, then it would be 10^11. I don't care if you
write 10^11 as 10x10^10; it's still wrong.

Dave Seaman
U.S. Court of Appeals to review three issues
concerning case of Mumia AbuJamal.
<http://www.mumia2000.org/> 

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Andrew Poelstra science forum beginner
Joined: 20 May 2006
Posts: 13

Posted: Wed Jul 12, 2006 5:30 am Post subject:
Re: Probability of 1234567890



On 20060712, Dave Seaman <dseaman@no.such.host> wrote:
Quote:  On Wed, 12 Jul 2006 02:41:04 GMT, Andrew Poelstra wrote:
On 20060711, Stig Holmquist <stigfjorden@hotmail.com> wrote:
What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?
Well, the number of permutations of 1234567890 is 10!
So, you have 10!/(10x10^10)
The number of ways of selecting 10 balls when sampling with replacement
is 10^10, not 10^11.

10*10^10 is 10^11. (I'm not sure if you factored that into your post or
not).

Andrew Poelstra <http://www.wpsoftware.net/projects/>
To email me, use "apoelstra" at the above domain.
"You people hate mathematics."  James Harris 

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Dave Seaman science forum Guru
Joined: 24 Mar 2005
Posts: 527

Posted: Wed Jul 12, 2006 3:23 am Post subject:
Re: Probability of 1234567890



On Wed, 12 Jul 2006 02:41:04 GMT, Andrew Poelstra wrote:
Quote:  On 20060711, Stig Holmquist <stigfjorden@hotmail.com> wrote:
What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?
Well, the number of permutations of 1234567890 is 10!
So, you have 10!/(10x10^10)

The number of ways of selecting 10 balls when sampling with replacement
is 10^10, not 10^11.

Dave Seaman
U.S. Court of Appeals to review three issues
concerning case of Mumia AbuJamal.
<http://www.mumia2000.org/> 

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Andrew Poelstra science forum beginner
Joined: 20 May 2006
Posts: 13

Posted: Wed Jul 12, 2006 2:41 am Post subject:
Re: Probability of 1234567890



On 20060711, Stig Holmquist <stigfjorden@hotmail.com> wrote:
Quote:  What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?

Well, the number of permutations of 1234567890 is 10!
So, you have 10!/(10x10^10)

Andrew Poelstra <http://www.wpsoftware.net/projects/>
To email me, use "apoelstra" at the above domain.
"You people hate mathematics."  James Harris 

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Dave Seaman science forum Guru
Joined: 24 Mar 2005
Posts: 527

Posted: Tue Jul 11, 2006 10:27 pm Post subject:
Re: Probability of 1234567890



On Tue, 11 Jul 2006 17:42:39 0400, Stig Holmquist wrote:
Quote:  What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?

The number of ways of drawing all ten digits, once each, is 10!. The total
number of possible draws is 10^10. The ratio, says Mathematica, is
In[1]:= 10!/10^10
567
Out[1]= 
1562500
In[2]:= N[%]
Out[2]= 0.00036288

Dave Seaman
U.S. Court of Appeals to review three issues
concerning case of Mumia AbuJamal.
<http://www.mumia2000.org/> 

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Stig Holmquist science forum beginner
Joined: 30 Apr 2005
Posts: 48

Posted: Tue Jul 11, 2006 9:42 pm Post subject:
Probability of 1234567890



What is the probability of drawing the digits
1234567890 in any oder when sampling
ten times with replacement from an urn with ten
balls numbered 1234567890 .
The probability of getting the same digit every
time would seem to be 1 per 10x10^10. So
to get the above set in any order must be
different. What formula should be used?
Stig Holmquist 

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