Search   Memberlist   Usergroups
 Page 1 of 1 [4 Posts]
Author Message
jpalmour@gmail.com
science forum beginner

Joined: 20 Jul 2006
Posts: 2

Posted: Thu Jul 20, 2006 8:48 pm    Post subject: Re: I need to know how it this equation was rearranged

q=Qmax(KdCw / 1+KdCw)
(1+KdCw)q=QmaxKdCw
q+KdCwq-QmaxKdCw=0
Kd(Cwq-QmaxCw)=-q
Kd=q/(QmaxCw-Cwq)
Kd=q/((Qmax-q)Cw)

Alicia wrote:
 Quote: q=Qmax(KdCw / 1+KdCw) original Kd= q / (Qmax-q) Cw is the rearranged but I need to know step by step which was the process to obtain de second equation rearranged or if someone have the rules to separate variables I'll be grateful.
stush@rocketmail.com

Joined: 10 Nov 2005
Posts: 73

Posted: Thu Jul 20, 2006 8:40 pm    Post subject: Re: I need to know how it this equation was rearranged

Alicia wrote:
 Quote: q=Qmax(KdCw / 1+KdCw) original Kd= q / (Qmax-q) Cw is the rearranged but I need to know step by step which was the process to obtain de second equation rearranged or if someone have the rules to separate variables I'll be grateful.

The rules are high school algerbra I would imagine.

I also imagine you have a mistake in your notation

q=Qmax(KdCw / 1+KdCw)

should be

q=Qmax(KdCw / (1+KdCw))

and

Kd= q / (Qmax-q) Cw

should be

Kd= q / ((Qmax-q) Cw)

Because I'm assuming you are using "/" to represent what in your
textbook is drawn with a horizontal line.

in which case doing it by hand, the steps would be

q=Qmax(KdCw / (1+KdCw)) to
q=(QmaxKdCw)/(1+KdCw) to
q + qKdCw = QmaxKdCw to
qKdCw - QmaxKdCw = -q to
Kd(qCw-QmaxCw) = -q to
Kd = -q/(qCW-QmaxCw) to
Kd = -q/((q-Qmax)Cw) to
Kd = q/((Qmax-q)Cw)
Dann Corbit
science forum beginner

Joined: 02 Jun 2006
Posts: 47

Posted: Thu Jul 20, 2006 8:39 pm    Post subject: Re: I need to know how it this equation was rearranged

"Alicia" <amarroquin@fmvz.uanl.mx> wrote in message
 Quote: q=Qmax(KdCw / 1+KdCw) original Kd= q / (Qmax-q) Cw is the rearranged but I need to know step by step which was the process to obtain de second equation rearranged or if someone have the rules to separate variables I'll be grateful.

Try it one step at a time. I imagine that there must be an error in your
original.

q=Qmax(KdCw / 1+KdCw) original

must really be:
q=Qmax(KdCw / (1+KdCw)) original

The parenthesis are not optional.

I have not bothered to work it out, but consider (for instance) that 1 =
Cw/Cw {assuming that Cw cannot become 0} and I think that might get you
started.
Alicia
science forum beginner

Joined: 09 Jun 2005
Posts: 17

 Posted: Thu Jul 20, 2006 8:31 pm    Post subject: I need to know how it this equation was rearranged q=Qmax(KdCw / 1+KdCw) original Kd= q / (Qmax-q) Cw is the rearranged but I need to know step by step which was the process to obtain de second equation rearranged or if someone have the rules to separate variables I'll be grateful.

 Display posts from previous: All Posts1 Day7 Days2 Weeks1 Month3 Months6 Months1 Year Oldest FirstNewest First
 Page 1 of 1 [4 Posts]
 The time now is Wed Jul 18, 2018 4:51 am | All times are GMT
 Jump to: Select a forum-------------------Forum index|___Science and Technology    |___Math    |   |___Research    |   |___num-analysis    |   |___Symbolic    |   |___Combinatorics    |   |___Probability    |   |   |___Prediction    |   |       |   |___Undergraduate    |   |___Recreational    |       |___Physics    |   |___Research    |   |___New Theories    |   |___Acoustics    |   |___Electromagnetics    |   |___Strings    |   |___Particle    |   |___Fusion    |   |___Relativity    |       |___Chem    |   |___Analytical    |   |___Electrochem    |   |   |___Battery    |   |       |   |___Coatings    |       |___Engineering        |___Control        |___Mechanics        |___Chemical

 Topic Author Forum Replies Last Post Similar Topics Help me plaese with this equation.. Rjames2 Math 0 Fri Oct 13, 2006 3:23 pm Differential equation bamford Symbolic 0 Thu Aug 10, 2006 3:44 pm How many different ways of this this equation.... aliprinter Math 6 Mon Jul 10, 2006 10:48 am How to solve this PDE (laplace equation)? wandering.the.cosmos@gmai Research 0 Sun Jul 09, 2006 4:20 am how to efficiently solve a relatively large scale linear ... zhaohf_2000@yahoo.com Research 0 Thu Jul 06, 2006 6:02 pm