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VijaKhara@gmail.com science forum beginner
Joined: 30 Sep 2005
Posts: 26

Posted: Sat May 27, 2006 1:37 pm Post subject:
is it correct?



Dear all
Today I read the book and the author deduces that
E(x^2)=0> P(x=0)=1//
I cannot understand why he got this result.
What do u think?
Thanks 

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VijaKhara@gmail.com science forum beginner
Joined: 30 Sep 2005
Posts: 26

Posted: Sat May 27, 2006 1:46 pm Post subject:
Re: is it correct?



all that I deduce is only following:
P(x=k)=0 if k!=0
for x=0, P(x=0) can be take any values <1 and E(x^2) is still equal
zero.
Plz confirm for me.
Thanks 

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VijaKhara@gmail.com science forum beginner
Joined: 30 Sep 2005
Posts: 26

Posted: Sat May 27, 2006 1:48 pm Post subject:
Re: is it correct?



Oh my second post is wrong, plz answer my first question. Thanks 

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Mike1170 science forum addict
Joined: 17 Sep 2005
Posts: 74

Posted: Mon May 29, 2006 4:58 am Post subject:
Re: is it correct?



<VijaKhara@gmail.com> wrote
Quote:  Dear all
Today I read the book and the author deduces that
E(x^2)=0> P(x=0)=1//
I cannot understand why he got this result.
What do u think?
All of the probability "mass" must be at x=0 for E(x^2) = 0. 


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