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VijaKhara@gmail.com
science forum beginner

Joined: 30 Sep 2005
Posts: 26

Posted: Sat May 27, 2006 1:37 pm    Post subject: is it correct?

Dear all
Today I read the book and the author deduces that
E(x^2)=0---> P(x=0)=1//

I cannot understand why he got this result.
What do u think?

Thanks
VijaKhara@gmail.com
science forum beginner

Joined: 30 Sep 2005
Posts: 26

 Posted: Sat May 27, 2006 1:46 pm    Post subject: Re: is it correct? all that I deduce is only following: P(x=k)=0 if k!=0 for x=0, P(x=0) can be take any values <1 and E(x^2) is still equal zero. Plz confirm for me. Thanks
VijaKhara@gmail.com
science forum beginner

Joined: 30 Sep 2005
Posts: 26

Posted: Sat May 27, 2006 1:48 pm    Post subject: Re: is it correct?

Oh my second post is wrong, plz answer my first question. Thanks
Mike1170

Joined: 17 Sep 2005
Posts: 74

Posted: Mon May 29, 2006 4:58 am    Post subject: Re: is it correct?

<VijaKhara@gmail.com> wrote
 Quote: Dear all Today I read the book and the author deduces that E(x^2)=0---> P(x=0)=1// I cannot understand why he got this result. What do u think? All of the probability "mass" must be at x=0 for E(x^2) = 0.

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