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Dobri Karagorgov science forum Guru Wannabe
Joined: 19 May 2005
Posts: 147
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Posted: Mon Jul 10, 2006 10:54 am Post subject:
EMITER is testing dedanoe
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emiter made a test on dedanoe's pmobile at:
http://dedanoe.tripod.com/success_story.html
the result is more then disapointing: from 140W input they output 5W
which is efficiency of 3.5% -- that is what they say and they are the
only macedonian scientific magazine. but they say that
resistor/consumer has to be connected to the output dynamo. this is
their schema:
accumulator=>x1 dynamo=>x2 dynamo=>ampermeter=>consumer
i say this way they were measuring the power of the resultant flow i.e.
produced power minus consumed power = resultant power and they say
dedanoe you produce the resultant power. it is very much the same as if
you plug the radio in the electrodistribution net and measure the watts
of the local flow:
Hover Dam=>wattmeter=>radio
it will show 10-15W because the radio has great resistance. it doesn't
mean that Hover Dam is producing 10-15W cause it is producing some
1.5TW. the great resistance of the radio is reducing the local flow
from optimum 1.5TW to 10-15W. i say they need to close the circuit in
the output dynamo directly with the ampermeter.
what do you think? |
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yt56erd science forum Guru
Joined: 13 May 2005
Posts: 313
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Posted: Mon Jul 10, 2006 11:00 am Post subject:
Re: EMITER is testing dedanoe
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dedanoe wrote:
shut up you raging faggot. you are too fucking thick to realise what
little clue you have. |
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CWatters science forum Guru Wannabe
Joined: 01 May 2005
Posts: 120
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Posted: Mon Jul 10, 2006 3:50 pm Post subject:
Re: EMITER is testing dedanoe
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"dedanoe" <dedanoe@yahoo.com> wrote in message
news:1152528852.797318.4140@m79g2000cwm.googlegroups.com...
| Quote: | emiter made a test on dedanoe's pmobile at:
http://dedanoe.tripod.com/success_story.html
the result is more then disapointing: from 140W input they output 5W
which is efficiency of 3.5% -- that is what they say and they are the
only macedonian scientific magazine. but they say that
resistor/consumer has to be connected to the output dynamo. this is
their schema:
accumulator=>x1 dynamo=>x2 dynamo=>ampermeter=>consumer
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If your device is producing more than 140W but only 5W is going to the
resistor... Where is the other 135W going?
We have a reasonably good idea where the rest of the output of the Hover dam
is going. |
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Paul Cardinale science forum Guru Wannabe
Joined: 08 May 2005
Posts: 177
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Posted: Mon Jul 10, 2006 4:07 pm Post subject:
Re: EMITER is testing dedanoe
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dedanoe wrote:
| Quote: | emiter made a test on dedanoe's pmobile at:
http://dedanoe.tripod.com/success_story.html
the result is more then disapointing: from 140W input they output 5W
which is efficiency of 3.5% -- that is what they say and they are the
only macedonian scientific magazine. but they say that
resistor/consumer has to be connected to the output dynamo. this is
their schema:
accumulator=>x1 dynamo=>x2 dynamo=>ampermeter=>consumer
i say this way they were measuring the power of the resultant flow i.e.
produced power minus consumed power = resultant power and they say
dedanoe you produce the resultant power. it is very much the same as if
you plug the radio in the electrodistribution net and measure the watts
of the local flow:
Hover Dam=>wattmeter=>radio
it will show 10-15W because the radio has great resistance. it doesn't
mean that Hover Dam is producing 10-15W cause it is producing some
1.5TW. the great resistance of the radio is reducing the local flow
from optimum 1.5TW to 10-15W. i say they need to close the circuit in
the output dynamo directly with the ampermeter.
what do you think?
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Don't expect useful replies. You have already demonstrated that you
are incapable of understanding them. |
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