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mathlover science forum beginner
Joined: 04 May 2005
Posts: 13
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Posted: Wed Jul 19, 2006 11:02 pm Post subject:
A Combinatorics/Graph Theory Question
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Hi every body,
There is a problem I have exposed to but, though being badly in need of
an answer, I have not yet been able to solve it. I am not quite sure if
it is better classified as a graph theory problem or a combinatorial
one; anyway, here is the problem:
Assume we have a bipartite graph with X and Y as its two parts. X has
"n" vertices and Y has C(k,n) vertices where "k" is a natural number
less than "n" and by C(k,n) I denote the number of k-element subsets of
an n-element set. The edges of the graph are formed as below: we
correspond each k-element subset of X with a vertex in Y and put an
edge between that vertex of Y and each member of the corresponding
k-element subset of X.
Now it is clear that for every vertex of X there are C(k-1, n-1)
vertices in Y that have an edge to that vertex. That is every vertex in
X has exactly C(k-1, n-1) number of neighbors in Y. Now the problem is
as follows: assuming "r" is a natural number not larger than C(k-1,
n-1) (I am specially interested in the case r=2) determine the minimum
number "p" (or at least a non-trivial upper bound on it) such that for
every p-element subset, like S, of Y the following property holds: for
every node in X, like "v", it has at least "r" neighbors which are
members of S.
Any help or clues are greatly appreciated.
Thanks. |
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Robert B. Israel science forum Guru
Joined: 24 Mar 2005
Posts: 2151
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Posted: Thu Jul 20, 2006 2:00 am Post subject:
Re: A Combinatorics/Graph Theory Question
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In article <1153350177.809822.112810@m79g2000cwm.googlegroups.com>,
mathlover <immathlover@yahoo.com> wrote:
| Quote: | Hi every body,
There is a problem I have exposed to but, though being badly in need of
an answer, I have not yet been able to solve it. I am not quite sure if
it is better classified as a graph theory problem or a combinatorial
one; anyway, here is the problem:
Assume we have a bipartite graph with X and Y as its two parts. X has
"n" vertices and Y has C(k,n) vertices where "k" is a natural number
less than "n" and by C(k,n) I denote the number of k-element subsets of
an n-element set. The edges of the graph are formed as below: we
correspond each k-element subset of X with a vertex in Y and put an
edge between that vertex of Y and each member of the corresponding
k-element subset of X.
Now it is clear that for every vertex of X there are C(k-1, n-1)
vertices in Y that have an edge to that vertex. That is every vertex in
X has exactly C(k-1, n-1) number of neighbors in Y. Now the problem is
as follows: assuming "r" is a natural number not larger than C(k-1,
n-1) (I am specially interested in the case r=2) determine the minimum
number "p" (or at least a non-trivial upper bound on it) such that for
every p-element subset, like S, of Y the following property holds: for
every node in X, like "v", it has at least "r" neighbors which are
members of S.
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Put another way:
What is the largest family S of k-element subsets of X = {1,...,n}
such that there are at most r-1 members of S containing 1?
Clearly you could take all C(n-1,k) k-element subsets of X that don't
contain 1, plus min(r-1, C(n-1,k-1) of the C(n-1,k-1) k-element
subsets of X that do contain 1, and you can't do better than that.
So your answer is p = C(n-1,k) + min(r-1, C(n-1,k-1)) + 1.
Robert Israel israel@math.ubc.ca
Department of Mathematics http://www.math.ubc.ca/~israel
University of British Columbia Vancouver, BC, Canada |
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Proginoskes science forum Guru
Joined: 29 Apr 2005
Posts: 2593
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Posted: Thu Jul 20, 2006 7:02 am Post subject:
Re: A Combinatorics/Graph Theory Question
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mathlover wrote:
| Quote: | Hi every body,
There is a problem I have exposed to but, though being badly in need of
an answer, I have not yet been able to solve it. I am not quite sure if
it is better classified as a graph theory problem or a combinatorial
one; anyway, here is the problem:
Assume we have a bipartite graph with X and Y as its two parts. X has
"n" vertices and Y has C(k,n) vertices where "k" is a natural number
less than "n" and by C(k,n) I denote the number of k-element subsets of
an n-element set. The edges of the graph are formed as below: we
correspond each k-element subset of X with a vertex in Y and put an
edge between that vertex of Y and each member of the corresponding
k-element subset of X.
Now it is clear that for every vertex of X there are C(k-1, n-1)
vertices in Y that have an edge to that vertex. That is every vertex in
X has exactly C(k-1, n-1) number of neighbors in Y. Now the problem is
as follows: assuming "r" is a natural number not larger than C(k-1,
n-1) (I am specially interested in the case r=2) determine the minimum
number "p" (or at least a non-trivial upper bound on it) such that for
every p-element subset, like S, of Y the following property holds: for
every node in X, like "v", it has at least "r" neighbors which are
members of S.
Any help or clues are greatly appreciated.
Thanks.
|
Your question seems to have been answered elsewhere. HOWEVER:
In the future, if you are going to post the same thing to more than
newsgroup, post it to both at once (this is called "cross-posting").
That way, people who read one newsgroup can see replies that the people
who read the other newsgroup have made.
--- Christopher Heckman |
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