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I need to know how it this equation was rearranged
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Alicia
science forum beginner


Joined: 09 Jun 2005
Posts: 17

PostPosted: Thu Jul 20, 2006 8:31 pm    Post subject: I need to know how it this equation was rearranged Reply with quote

q=Qmax(KdCw / 1+KdCw) original

Kd= q / (Qmax-q) Cw is the rearranged

but I need to know step by step which was the process to obtain
de second equation rearranged or if someone have the rules to separate
variables I'll be grateful.
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Dann Corbit
science forum beginner


Joined: 02 Jun 2006
Posts: 47

PostPosted: Thu Jul 20, 2006 8:39 pm    Post subject: Re: I need to know how it this equation was rearranged Reply with quote

"Alicia" <amarroquin@fmvz.uanl.mx> wrote in message
news:1153427506.198033.256890@s13g2000cwa.googlegroups.com...
Quote:
q=Qmax(KdCw / 1+KdCw) original

Kd= q / (Qmax-q) Cw is the rearranged

but I need to know step by step which was the process to obtain
de second equation rearranged or if someone have the rules to separate
variables I'll be grateful.

Try it one step at a time. I imagine that there must be an error in your
original.

q=Qmax(KdCw / 1+KdCw) original

must really be:
q=Qmax(KdCw / (1+KdCw)) original

The parenthesis are not optional.

I have not bothered to work it out, but consider (for instance) that 1 =
Cw/Cw {assuming that Cw cannot become 0} and I think that might get you
started.
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stush@rocketmail.com
science forum addict


Joined: 10 Nov 2005
Posts: 73

PostPosted: Thu Jul 20, 2006 8:40 pm    Post subject: Re: I need to know how it this equation was rearranged Reply with quote

Alicia wrote:
Quote:
q=Qmax(KdCw / 1+KdCw) original

Kd= q / (Qmax-q) Cw is the rearranged

but I need to know step by step which was the process to obtain
de second equation rearranged or if someone have the rules to separate
variables I'll be grateful.

The rules are high school algerbra I would imagine.

I also imagine you have a mistake in your notation

q=Qmax(KdCw / 1+KdCw)

should be

q=Qmax(KdCw / (1+KdCw))

and

Kd= q / (Qmax-q) Cw

should be

Kd= q / ((Qmax-q) Cw)

Because I'm assuming you are using "/" to represent what in your
textbook is drawn with a horizontal line.

in which case doing it by hand, the steps would be

q=Qmax(KdCw / (1+KdCw)) to
q=(QmaxKdCw)/(1+KdCw) to
q + qKdCw = QmaxKdCw to
qKdCw - QmaxKdCw = -q to
Kd(qCw-QmaxCw) = -q to
Kd = -q/(qCW-QmaxCw) to
Kd = -q/((q-Qmax)Cw) to
Kd = q/((Qmax-q)Cw)
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jpalmour@gmail.com
science forum beginner


Joined: 20 Jul 2006
Posts: 2

PostPosted: Thu Jul 20, 2006 8:48 pm    Post subject: Re: I need to know how it this equation was rearranged Reply with quote

q=Qmax(KdCw / 1+KdCw)
(1+KdCw)q=QmaxKdCw
q+KdCwq-QmaxKdCw=0
Kd(Cwq-QmaxCw)=-q
Kd=q/(QmaxCw-Cwq)
Kd=q/((Qmax-q)Cw)

Alicia wrote:
Quote:
q=Qmax(KdCw / 1+KdCw) original

Kd= q / (Qmax-q) Cw is the rearranged

but I need to know step by step which was the process to obtain
de second equation rearranged or if someone have the rules to separate
variables I'll be grateful.
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