| Author |
Message |
WingDragon@gmail.com
science forum beginner
Joined: 21 Jul 2006
Posts: 2
|
 Posted: Fri Jul 21, 2006 8:13 am Post subject:
Question about exponention
|
|
|
How can I calculate such a large value like this?
2^(5^49) = ?
I can't calculate the result by any calculator. Is there any way to
find the answer more easily?
Thanks and sorry for my poor English.
Fred |
|
| Back to top |
|
 |
WingDragon@gmail.com
science forum beginner
Joined: 21 Jul 2006
Posts: 2
|
| Posted: Fri Jul 21, 2006 8:25 am Post subject:
Re: Question about exponention
|
|
|
sorry, I have missed something...
should be:
2^(5^49) mod 29 = ?
WingDragon@gmail.com 寫道：
| Quote: | How can I calculate such a large value like this?
2^(5^49) = ?
I can't calculate the result by any calculator. Is there any way to
find the answer more easily?
Thanks and sorry for my poor English.
Fred |
|
|
| Back to top |
|
|
William Elliot
science forum Guru
Joined: 24 Mar 2005
Posts: 1906
|
| Posted: Fri Jul 21, 2006 9:06 am Post subject:
Re: Question about exponention
|
|
|
On Fri, 21 Jul 2006 WingDragon@gmail.com wrote:
| Quote: | sorry, I have missed something...
should be:
2^(5^49) mod 29 = ?
Golly, another ##$@%^ computer problem. |
2^28 = 1 (mod 29)
phi(2 = phi 4 * phi 7 = 2 * 6 = 12
5, 28 coprime
5^12 = 1 (mod 28)
5^49 = 5^(4*12) * 5 = 5 (mod 2
2^(5^49) = 2^5 = 32 = 3 (mod 29)
| Quote: | WingDragon@gmail.com 寫道：
How can I calculate such a large value like this?
2^(5^49) = ?
I can't calculate the result by any calculator.
|
That's because calculators are stupid.
Can they calculate the simple equivalence?
25 = 5 (mod 5)
| Quote: | Is there any way to find the answer more easily?
|
Yes, but only if you dare to turn off the computer and do your own
thinking. |
|
| Back to top |
|
|
Google
|
|
| Back to top |
|
|
|
FAQ
Search
Memberlist
Usergroups
Register
Profile
Log in to check your private messages
Log in
Forum index
»
Science and Technology
»
Math
