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A type of 3.1.5 equation
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Tony177
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PostPosted: Fri Jun 16, 2006 1:51 pm    Post subject: A type of 3.1.5 equation Reply with quote

Where a and b are free variables. a^3 + b^3 + (b*2)^3 + (b*b*3/a)^3 + (b*b*b*3/a*a)^3 = ((b*b*b*3/a*a)+a)^3 .To simplify,lets make a=1.Now for the smallest in whole numbers,1^3+1^3+2^3+3^3+3^3=4^3.if we wish to keep a as 1 and change b to 2: 1^3+2^3+4^3+12^3+24^3=25^3.
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